-2w^2-6w+80=0

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Solution for -2w^2-6w+80=0 equation:



-2w^2-6w+80=0
a = -2; b = -6; c = +80;
Δ = b2-4ac
Δ = -62-4·(-2)·80
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*-2}=\frac{-20}{-4} =+5 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*-2}=\frac{32}{-4} =-8 $

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